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- The
**Lorentz force**on a charged particle due to electric and magnetic fields is**F**= q (**E**+**v ⊗ B**)**magnetic field B**is measured in**Tesla**(1 T ≡ 1 N / (A m)). If**E**is 0,**F**is always perpendicular to**v**and acts as a centripetal acceleration.If

**E**= 0 and the charges are part of a**current element**I moving in the direction**dl**,**F**= I ∫**dl ⊗ B** - For a
**current loop**with n loops and area A, define the**magnetic moment**:**μ**= n I**A****μ**is most conveniently given by the**right hand rule**: if the fingers of your right hand follow in the direction of the current, your right thumb points in the direction of the moment.Then in a magnetic field,

**τ**=**μ ⊗ B**and U = -**μ ⋅ B**.

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©2010, Kenneth R. Koehler. All Rights Reserved. This document may be freely reproduced provided that this copyright notice is included.